Hello 8ball4116,
I’ve never used spherical coordinates so I assumed that these figures were of a spherical coordinates nature. So I did the following:-

Command: _line Specify first point: 0,0
Specify next point or [Undo]: <Ortho off> 3.5<56.4<-25
Specify next point or [Undo]:

I then activated the LIST command and got the following:-
Command: _list
Select objects: 1 found
Select objects:
LINE Layer: "0"
Space: Model space
Handle = 7423
from point, X= 0.00 Y= 0.00 Z= 0.00
to point, X= 1.76 Y= 2.64 Z= -1.48
In Current UCS, Length = 3.17, Angle in XY Plane = 56.40
3D Length = 3.50, Angle from XY Plane = 335.00
Delta X = 1.76, Delta Y = 2.64, Delta Z = -1.48

I then viewed the line from a 3d viewpoint by using Orbit to see for myself where it went:-

Command: '_3dorbit Press ESC or ENTER to exit, or right-click to display
shortcut-menu.
Regenerating model.

I then also activated the .id command, picked the far end of the line and got the following:-
Command: '_id Specify point: X = 1.76 Y = 2.64 Z = -1.48

Activate the Help file and type in spherical coordinates.
The description & diagram are worth reading.

You could also put @ in front of your equation:- @3.5<56.4<-25 and this will give you a line from wherever you want to start, 3.5 units long in the specified direction.
Your line is therefor 3.5 units long & it appears to be within the positive quadrant of the x& y, but below ‘ground zero’ by –1.48 units(-z).

I hope this will be of some help to you.

I can only imagine that saying ''spherical co-ordinates information extraction'' repeatedly at the end of a marthon pub crawl would get you a resounding round of applause!

regards

Stephen